Enviar a tu servidor
Zavilo returns browser File objects, so standard multipart/form-data upload patterns work without conversion.
Single file
const form = new FormData();
form.append("file", result.files[0], result.files[0].name);
await fetch("/api/upload", {
method: "POST",
body: form
});Multiple files
const form = new FormData();
for (const file of result.files) {
form.append("files", file, file.name);
}
form.append("executionId", result.executionId);
await fetch("/api/upload-many", {
method: "POST",
body: form
});ZIP archive
if (result.archive) {
const form = new FormData();
form.append(
"file",
result.archive.file,
result.archive.file.name
);
await fetch("/api/upload-archive", {
method: "POST",
body: form
});
}Your upload URL belongs to your application. Zavilo does not choose where your service stores generated files.